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(, 05:05 PM)qwerty Wrote: (, 09:47 AM)radix Wrote: You didn't specify a mask.Yes, I know. But what it will be correct mask if i want break password with a.z, A.Z, 0.9 in all combinations?I don't understand this:-1?l?u?d?1?1?1?1?1 etc.-1 = customcharset, same for -2, -3, -4?l: Loweralpha or more specificaly = abcdefghijklmnopqrstuvwxyz?u: UperCase or more specificaly = ABCDEFGHIJKLMNOPQRSTUVWXYZ?d: Digits or more specificaly = & '?1' is the length so if you whant to BF an 4 Length one:?1?1?1?1. (, 06:13 PM)qwerty Wrote: Strange.My command is:cudaHashcat-plus64.exe -hash-type 2500 -attack-mode 3 -custom-charset1?l?u?d C:UsersqwertyDesktop083646.hccap?1?1?1?1?1and something is strange:Speed.: 0 c/s Real, 0 c.s GPUProgress: 12082832 (13,19%)Rejected.: 12004151 (100%)HW.Monitor.#1: 0% GPU, 43c TempWPA key length is minimum of 8, you have set a mask of 5 and are getting rejected.cudaHashcat-plus64.exe -hash-type 2500 -attack-mode 3 -custom-charset1?l?u?d C:UsersqwertyDesktop083646.hccap?1?1?1?1?1?1?1?1.
New submitter Woodmeister shares a report: While looking for ways to attack the new WPA3 security standard, Hashcat developer Jens 'Atom' Steube found a simpler way to capture and crack access credentials protecting WPA and WPA2 wireless networks. The attacker needs to capture a single EAPOL frame.